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4.9x^2-9.5x-44=0
a = 4.9; b = -9.5; c = -44;
Δ = b2-4ac
Δ = -9.52-4·4.9·(-44)
Δ = 952.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{952.65}}{2*4.9}=\frac{9.5-\sqrt{952.65}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{952.65}}{2*4.9}=\frac{9.5+\sqrt{952.65}}{9.8} $
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